Fluid Statics
The key concepts to learn in this chapter are pressure with depth in a static fluid
and buoyancy. We begin with the definition of the density of a substance:
r = mass/volume
and the definition of pressure:
P = force/area.
The air exerts a static pressure of 1.01 x 105 N/m2 (Pascals)
all around us (click here for a discussion of this)
due to its own weight; this pressure is also exerted within a container of water open to the
atmosphere. At a depth of h = 10 meters in plain water, the pressure
(acting in all directions at once) is a combination of the
atmospheric pressure and the pressure of the water due to the weight of water above:
Ptot = Patm + Pfluid
where
Pfluid = rgh.
Using the information above, the extra fluid pressure (also called gauge pressure)
is (1000 kg/m3)x(9.8 m/s2)x(10 m) = 0.98 x 105 Pascals, which
is about one atmosphere's worth of extra pressure.
The density of water is 1000 kg/m3, and serves as a standard for comparison.
Water is much more dense than air, which is why a depth of only 10 m of water exerts a similar
pressure on you compared to about 6 miles of air.
The fact that there is greater pressure at lower depths in a fluid than close to the surface
explains why there is an upward force (called buoyant force) on any submerged object.
If the downward pressure on the object's top surface is P1, then the upward pressure
on the object's bottom surface is P1 + rgh (where h is
the height of the object). The net upward force is the difference between these pressures
(DP) times the cross-sectional area of the object (A), or
buoyant force
FB =
(rwater)(gh)(A) =
(rwater)(Vobject)(g),
which turns out to be equal to the weight of the water that has been displaced by
the object (the weight of an equivalent volume of water; a.k.a Archimede's
Principle). This means that if the object
immersed in the water is more dense than water, its weight will exceed this upward buoyant
force and it will sink; and if the object immersed in the water is less dense than
water, its weight will be less than this upward buoyant force and it will float.
Typical problems you will learn to solve:
- calculating the height that an IV bag has to be
placed above the level of a needle for there to be infusion into the bloodstream.
- calculating the buoyant force acting on a submerged object or on a floating object; or
determining if the described object will float or sink when placed in a fluid in a certain way.
The pitfalls involved in these problems (and concepts I will test you on) include:
- not using correct units to calculate gauge pressure or density. Convert depths to
meters, pressures to Pascals, volumes to cubic meters, etc. before plugging into equations.
- not using given information in solving the problem. For example: I might tell you that
the fluid is seawater or blood rather than water, so you should use the
appropriate fluid density to calculate gauge pressure and/or buoyant force.
- forgetting that pressure and force are not the same thing. You have to multiply pressure
by area over which it acts in order to get the force.
- forgetting that atmospheric pressure acts on both sides of any container wall (except
where there is a partial or total vacuum). For infusion problems or problems involving leaking
containers, flow is caused by any DP, which means that
atmospheric pressure "cancels out" when you calculate the net force. But by the same
token, you should know how to calculate the total pressure if I ask for that; then you
would have to include Patm.
- confusing the equation for the weight of a submerged object with the equation for buoyant
force on that object. Often I will give you the density of the submerged object, from which
you can calculate its weight using Fg =
(robj)(Vobj)(g). You are then supposed to
calculate the buoyant force and compare it with the weight, in order to show that the object
floats or sinks. You can't use the object's density
to calculate buoyant force; you need the density of the fluid instead.
- forgetting that the buoyant force on an object depends on how much of that object is
immersed in a fluid. There is less buoyant force when it is only partially submerged.
- forgetting that the buoyant force on a totally-submerged object does not depend on the
depth of fluid, or on what other forces might be acting on the object (such as normal force).
Click here for some test-level practice problems.
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